Comments for Lettergram.net http://lettergram.net A quicker approach to learning. Thu, 08 Mar 2012 04:40:04 +0000 hourly 1 http://wordpress.org/?v=3.3.2 Comment on Kinematics in the One Dimension by Projectile Motion | Lettergram.net http://lettergram.net/linear-motion-kinematics-in-the-one-direction/#comment-66 Projectile Motion | Lettergram.net Thu, 08 Mar 2012 04:40:04 +0000 http://lettergram.net/?p=48#comment-66 [...] ** All equations come from: Kinematic Equations [...] [...] ** All equations come from: Kinematic Equations [...]

]]> Comment on Projectile Motion by lettergram http://lettergram.net/projectile-motion/#comment-60 lettergram Mon, 05 Mar 2012 23:10:42 +0000 http://lettergram.net/?p=128#comment-60 Then yes, my answer: <blockquote>yf = yi + Vit + (1/2)at^2 yi = 125m yf = 0 V = 0 (starting in the y direction it is zero) a = 9.8m/s^2 on earth 0 = 125m + 0 - (1/2)a*t^2 125m/(1/2) = a * t^2 a = 9.8 m/s^2 250m/(9.8m/s^2) = t^2 25.51s^2 = t^2 square root both sides! 5.05 seconds (SO CORRECT) For speed it is simple: time * acceleration due to gravity (because the skier is falling) (5.05s)*(9.8m/s^2) = 49.5 m/s</blockquote> Would all be correct, if they asked for total velocity you would need to take into account the horizontal velocity and calculate the angle at which he was hitting the ground. I just wanted to make sure in order to not give you a wrong answer. :) If you have any more questions feel free to post here (Sorry, it may take me 24 hours or so to respond though because I am fairly busy). Anyways hope I helped! Then yes, my answer:

yf = yi + Vit + (1/2)at^2

yi = 125m
yf = 0
V = 0 (starting in the y direction it is zero)
a = 9.8m/s^2 on earth

0 = 125m + 0 – (1/2)a*t^2
125m/(1/2) = a * t^2

a = 9.8 m/s^2

250m/(9.8m/s^2) = t^2

25.51s^2 = t^2

square root both sides!

5.05 seconds (SO CORRECT)

For speed it is simple:

time * acceleration due to gravity (because the skier is falling)

(5.05s)*(9.8m/s^2) = 49.5 m/s

Would all be correct, if they asked for total velocity you would need to take into account the horizontal velocity and calculate the angle at which he was hitting the ground. I just wanted to make sure in order to not give you a wrong answer. :)

If you have any more questions feel free to post here (Sorry, it may take me 24 hours or so to respond though because I am fairly busy). Anyways hope I helped!

]]> Comment on Projectile Motion by Jack Rydre http://lettergram.net/projectile-motion/#comment-59 Jack Rydre Mon, 05 Mar 2012 21:03:32 +0000 http://lettergram.net/?p=128#comment-59 A skier lauches off a ramp with a horizontal velocity of 30ms/s and falls through a vertical height of 125m...(thats the problem) Hi, I asked this question on yahoo and you wanted me to be more specific. What the question asks is: What is his vertical velocity when he lands? Thanks for any help A skier lauches off a ramp with a horizontal velocity of 30ms/s and falls through a vertical height of 125m…(thats the problem)
Hi, I asked this question on yahoo and you wanted me to be more specific. What the question asks is: What is his vertical velocity when he lands?
Thanks for any help

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